sciPy stats.trimboth()函数| Python
原文:https://www.geesforgeks.org/scipy-stats-trimboth-function-python/
scipy.stats.trimboth(a，proportiontocut，axis=0) 函数从数组的两端切掉数组中的部分元素。
参数: arr:【array _ like】输入要修剪的数组或对象。 轴:计算平均值的轴。默认情况下，轴= 0。 比例分配:每端要修剪的数据比例(在 0-1 范围内)。
结果:按照给定的比例从两端修剪数组元素。
代码#1:工作
# stats.trimboth() method
import numpy as np
from scipy import stats
arr1 = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
print ("\narr1 : ", arr1)
print ("\nclipped arr1 : \n", stats.trimboth(arr1, proportiontocut = .3))
print ("\nclipped arr1 : \n", stats.trimboth(arr1, proportiontocut = .1))
输出:
arr1 : [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
clipped arr1 :
[3 4 5 6]
clipped arr1 :
[1 3 2 4 5 6 7 8]
代码#2:
# stats.trimboth() method
import numpy as np
from scipy import stats
arr1 = [[0, 12, 21, 3, 14],
[53, 16, 37, 85, 39]]
print ("\narr1 : ", arr1)
print ("\nclipped arr1 : \n",
stats.trimboth(arr1, proportiontocut = .3))
print ("\nclipped arr1 : \n",
stats.trimboth(arr1, proportiontocut = .1))
print ("\nclipped arr1 : \n",
stats.trimboth(arr1, proportiontocut = .1, axis = 1))
print ("\nclipped arr1 : \n",
stats.trimboth(arr1, proportiontocut = .1, axis = 0))
输出:
arr1 : [[0, 12, 21, 3, 14], [53, 16, 37, 85, 39]]
clipped arr1 :
[[ 0 12 21 3 14]
[53 16 37 85 39]]
clipped arr1 :
[[ 0 12 21 3 14]
[53 16 37 85 39]]
clipped arr1 :
[[ 0 3 12 14 21]
[16 37 39 53 85]]
clipped arr1 :
[[ 0 12 21 3 14]
[53 16 37 85 39]]
